Pentagonal pyramid

A pentagonal pyramid is a pyramid where the base is a pentagon. The figure therefore has a total of six faces.

One pentagonal base and five triangular side faces.

 

If the base is a regular pentagon and the apex is placed directly above the center, it is called a regular pentagonal pyramid. If the apex is not centered, the pyramid is irregular.

 

 

Pentagonal pyramid

 

 

Volume

The volume of a pentagonal pyramid is found by multiplying the area of the base by the height and then dividing by 3:

 

$$ \large V = \frac{1}{3} \cdot A_{base} \cdot h $$

 

For a regular pentagon with side length \( \large a \), the area of the base can be calculated as:

 

$$ \large A_{base} = \frac{5}{4} \cdot a^2 \cdot \cot\left(\frac{\pi}{5}\right) $$

 

Thus, the volume of a regular pentagonal pyramid is:

 

$$ \large V = \frac{1}{3} \cdot \frac{5}{4} \cdot a^2 \cdot \cot\left(\frac{\pi}{5}\right) \cdot h $$

 

 

Surface area

The surface area consists of the area of the base plus the area of the five triangular side faces:

 

$$ \large S = A_{base} + A_{sides} $$

 

If the pyramid is regular, all side faces are congruent, and one can write:

 

$$ \large S = A_{base} + 5 \cdot A_{triangle} $$

 

 

Irregular pentagonal pyramid

In an irregular pentagonal pyramid, the apex is not placed above the center of a regular pentagon. The base can be any pentagon, and the side faces are not necessarily equal.

 

Irregular pentagonal pyramid

 

 The volume is still found as:

 

$$ \large V = \frac{1}{3} \cdot A_{base} \cdot h $$

 

The surface area in this case requires calculating the area of each triangular side face separately and adding them together with the area of the base:

 

$$ \large S = A_{base} + \sum_{i=1}^{5} A_{triangle,i} $$

 

 

 

Calculator

Formulas

Base area

$$ A_{base} = \frac{5}{4} \cdot a^2 \cdot \cot\left(\frac{\pi}{5}\right) $$

Volume

$$ V = \frac{1}{3} \cdot \frac{5}{4} \cdot a^2 \cdot \cot\left(\frac{\pi}{5}\right) \cdot h $$

Height

$$ h = \frac{12 \cdot V}{5 \cdot a^2 \cdot \cot\!\left(\tfrac{\pi}{5}\right)} $$

Side a

$$ a = \sqrt{\frac{12 \cdot V}{5 \cdot h \cdot \cot\!\left(\tfrac{\pi}{5}\right)}} $$